please.... bantuin dong... caranya gimana.... isinya tuh 2/s^3

[tex]\int_0^{\infty}e^{-st}t^2$ $dt \\ U=t^2, dV=e^{-st} \\ U'=2t, V = -\frac{1}{s}e^{-st} \\ \int UdV= UV - \int VdU \\ t^2\times -\frac{1}{s}e^{-st} - (2t\times \frac{1}{s^2}e^{-st}) + 2\times -\frac{1}{s^3}e^{-st}]_0^{\infty} \\ (e^{-\infty}=0) \\ (0)-(0-0+2\times\frac{1}{s^3}e^{-s.0}) \\ -\frac{2}{s^3}e^0 \\ -\frac{2}{s^3}[/tex]