tolong di bantu kawan kawan no 15
Matematika
roy228
Pertanyaan
tolong di bantu kawan kawan no 15
1 Jawaban
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1. Jawaban Anonyme
jawab
f(x,y) = x + 3y
titik titik sudut
(1,3) → f(x,y) = 1 + 3(3) =10
(2,2) → f(x,y) = 2 + 3(2)= 8
(3,5) → f(x,y) = 3 + 3(5) = 18
(5,3) → f(x,y) = 5 + 3(3) = 14
(6,4) → f(x,y) = 6 + 4(3)= 18
maksimum = 18