Matematika

Pertanyaan

tolong di bantu kawan kawan no 15
tolong di bantu kawan kawan no 15

1 Jawaban

  • jawab

    f(x,y) = x + 3y
    titik titik sudut
    (1,3) → f(x,y) = 1 + 3(3) =10
    (2,2) → f(x,y) = 2 + 3(2)= 8
    (3,5) → f(x,y) = 3 + 3(5) = 18
    (5,3) → f(x,y) = 5 + 3(3) = 14
    (6,4) → f(x,y) = 6 + 4(3)= 18
    maksimum = 18