Tolong dibantu caranya... Terima kasih ^.^
Matematika
4m3L14L
Pertanyaan
Tolong dibantu caranya...
Terima kasih ^.^
Terima kasih ^.^
1 Jawaban
-
1. Jawaban Sutr1sn0
(x - 2)/(2x - 4) + (x + 4)/(2x + 4)
--------------------------------------------
(x + 5)/(2x + 4) - (x - 4)/(2x - 4)
...(x -2)(2x + 4)........(x + 4)(2x - 4)
...-------------------- + ----------------------
...(2x - 4)(2x + 4)....(2x - 4)(2x + 4)
= ---------------------------------------------
...(x + 5)(2x - 4)........(x - 4)(2x + 4)
...--------------------- - -----------------------
...(2x + 4)(2x - 4)......(2x + 4)(2x - 4)
...(2x^2 - 8)...... (2x^2 + 4x - 16)
...--------------- + -------------------------
...(4x^2 - 16)............(4x^2 - 16)
= --------------------------------------------------
...(2x^2 + 6x - 20)......(2x^2 - 4x - 16)
...------------------------ - -----------------------
...(4x^2 - 16) ...............(4x^2 - 16)
...(4x^2 + 4x - 24)/(4x^2 - 16)
= ---------------------------------------
..........(10x - 4)/(4x^2 - 16)
...(4x^2 + 4x - 24).......(4x^2 - 16)
= ----------------------- × -----------------
........(4x^2 -16)...............(10x - 4)
...(4x^2 + 4x - 24)
= -----------------------
...........(10x - 4)
...2(2x^2 + 2x - 12)
= ------------------------
...........2(5x - 2)
...2x^2 + 2x - 12
= ----------------------
..........5x - 2