Matematika

Pertanyaan

Tolong dibantu caranya...

Terima kasih ^.^
Tolong dibantu caranya... Terima kasih ^.^

1 Jawaban

  • (x - 2)/(2x - 4) + (x + 4)/(2x + 4)
    --------------------------------------------
    (x + 5)/(2x + 4) - (x - 4)/(2x - 4)


    ...(x -2)(2x + 4)........(x + 4)(2x - 4)
    ...-------------------- + ----------------------
    ...(2x - 4)(2x + 4)....(2x - 4)(2x + 4)
    = ---------------------------------------------
    ...(x + 5)(2x - 4)........(x - 4)(2x + 4)
    ...--------------------- - -----------------------
    ...(2x + 4)(2x - 4)......(2x + 4)(2x - 4)


    ...(2x^2 - 8)...... (2x^2 + 4x - 16)
    ...--------------- + -------------------------
    ...(4x^2 - 16)............(4x^2 - 16)
    = --------------------------------------------------
    ...(2x^2 + 6x - 20)......(2x^2 - 4x - 16)
    ...------------------------ - -----------------------
    ...(4x^2 - 16) ...............(4x^2 - 16)


    ...(4x^2 + 4x - 24)/(4x^2 - 16)
    = ---------------------------------------
    ..........(10x - 4)/(4x^2 - 16)


    ...(4x^2 + 4x - 24).......(4x^2 - 16)
    = ----------------------- × -----------------
    ........(4x^2 -16)...............(10x - 4)


    ...(4x^2 + 4x - 24)
    = -----------------------
    ...........(10x - 4)


    ...2(2x^2 + 2x - 12)
    = ------------------------
    ...........2(5x - 2)

    ...2x^2 + 2x - 12
    = ----------------------
    ..........5x - 2