jawablah lampiran ini

Persamaan Kuadrat

1][
x² + 5x + 4 = 0
(x + 1)(x + 4) = 0
x = -1 atau x = -4 ✔

2][
2x² - 7x + 3 = 0
a = 2
b = -7
c = 3

x1.2 = (-b ± √(b² - 4ac))/(2a)
x1.2 = (7 ± √(49 - 24))/4
x1.2 = (7 ± 5)/4
x1 = (7 + 5)/4 = 3 ✔
x2 = (7 - 5)/4 = 1/2 ✔

3][
2x² + 5x + 3 = 0
Cek nilai D nya
D = b² - 4ac = 25 - 24 = 1
D > 0
akar2 real berlainan ✔

4][
2x² - 7x + 3 = 0
(2x - 1)(x - 3) = 0
x1 = 1/2 atau x2 = 3
••
x1/x2 + x2/x1 = 1/6 + 6 = 6 1/6 = 37/6 ✔

5][
Persamaan Kuadrat dg akar2 2 dan -5 :
(x - 2)(x + 5) = 0
x² + 3x - 10 = 0 ✔

6][
PK lama : x² + 4x + 3 = 0

PK baru dg akar2 (x1 - 1) dan (x2 - 1) :
(x + 1)² + 4(x + 1) + 3 = 0
x² + 6x + 8 = 0 ✔