persamaan garis yang melalui titik(4,-3) dan tegak lurus garis 2x-y=0

[tex]2x - y = 0 \\ - y = - 2x 2\\ y = 2x[/tex]
m = 2

M1.M2 = -1
2 . M2 = -1
M2. = 1/2 . -1
M2. = -1/2

y - y1 = m (x-x1)
y-(-3) = -1/2 (x-4)
y + 3 = -1/2x + 4/2
y = -1/2x + 4/2 + 6/2
y. = -1/2x + 10/2
2y. = -x + 10

maaf kalau salah