Matematika

Pertanyaan

1.pengurangan pecahan
A.15,2/3 - 7,3/4
B.6,1/3 - 8,2/3
C.5,1/6 - 13,2/3
D.7 - ... = 5,3/7
E.10,2/3 - ... = 5,1/5

2.Penjumlahan pecahan
A.2/3 + ... = 5/6
B.2,1/5 + ... =5,3/7

1 Jawaban

  • 15 ⅔ - 7 ¾
    = 47/3 - 31/4
    = 95/12
    = [tex] 7 \frac{11}{12} [/tex]

    6 ⅓ - 8 ⅔
    = 19/3 - 26/3
    = - 7/3

    5 ⅙ - 13 ⅔
    = 31/6 - 41/3
    = - 17/2
    = - 8 ½

    7 - x = 5 [tex] \frac{3}{7} [/tex]
    x = 7 - 38/7
    x = 11/7
    x = 1 [tex] \frac47 [/tex]

    10 ⅔ - x = 5 ⅕
    x = 32/3 - 26/5
    x = 82/15
    x = 5 [tex] \frac{7}{15} [/tex]

    Penjumlahan
    ⅔ + x = ⅚
    x = ⅚ - ⅔
    x = ⅙

    2 ⅕ + x = 5 ³/₇
    x = 38/7 - 11/5
    x = 3 [tex] \frac8{35} [/tex]

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