tentukan nilai kombinasi a. 4C2 b. 12C7

A) 4 C 2 = 4! / (4-2)!.2!
= 4.3.2! / 2!.2.1
= 4.3/2
= 6
B) 12 C 7 = 12! /(12-7)!.7!
= 12.11.10.9.8.7! / 5!.7!
= 12.11.10.9.8 / 5.4.3.2.1
= 12.11.10.9.8 / 5.2.4.3 (5.2= 10, 4.3 = 12), maka
= 11.9.8
= 792

a. 4C2 = 4!/2! (4-2)!
= 4.3.2.1/2.1.2.1
= 24/4
= 6
b. 12C7 = 12!/7! (12-7)!
= 12.11.10.9.8.7! / 7! 5.4.3.2.1
= 792