tentukan persamaan garis melalui titik e (-4,10) dan f (-6,2)

m= y²-y¹/x²-x¹
= 2-10/-6-(-4)
= -8/-2
= 4

gradien=m=2-10/-6-(-4)=-8/-2=4
pers garis
=y-y1=m(x-x1)
y-2=4(x-(-6)
y-2=4x+24
y-4x=26. /. y-4x-26=0