Nilai minimum dari f(x) = ax^2 + 2x +8 adalah 5, nilai 6a adalah

jawab

f(x)= ax² + 2x + 8
nilai minimum =  5
b²- 4ac/ -4a  = 5
(2²) - 4(a)(8) = 5(4a)
4 + 32 a =  20 a
32 a - 20 a = - 4
12 a = - 4
a = - 1/3

nilai 6a = 6 (-1/3) = - 2

Jawab :

f (×) = a×2 + 2× +8
nilai minuman 5
b2 - 4ac / -4a = 5
(2 pangkat 2) - 4(a)(8) = 5(4a)
4 + 32 a = 20 a
32 a - 20 a = -4
12 a = -4
a=1/3

Jadi nilai 6a = 6(-1/3)=-2