Hasil dari (4a+3)³ Pakai caranya...

(4a+3)^3
= (4a+3)(4a+3)(4a+3)
=16a+12a+16a+12a+12a+9+12a+9+16a+12a+12a+9
= ((16a×3)+(12a×6)) + (9×3)
= (48a+72a) + 27
= 120a + 27

(4a)³+3.(4a)².3+3.(4a).3²+3³ =48a³+144a²+108a²+27. Mohon maaf jika salah