x log (x²+x+1)=x log 13 tolong dijawab yaa... pakai cara :3

x log (x²+x+1)=x log 13
⇔ x² + x + 1 = 13
⇔ x² + x - 12 = 0
⇔ (x + 4)(x - 3) = 0
x = -4   atau   x = 3

HP : {-4, 3}