Jika a=0,9090..... dan b= 1,331 ,maka alog b =

Bab Logaritma
Matematika SMA Kelas X

^ = pangkat

a = 0,9090... 
   = 10/11

b = 1,331 
   = 1,1³
   = (11/10)³


ᵃlog b = ^(10/11)log (11/10)³
          = ^(10/11)log (11/10)⁻³
          = (-3) . ^(10/11)log (11/10)
          = -3

jawabannya A

LogAritMa

a = 0,9090...
100a = 90,90...
99a = 90
a = 10/11

b = 1,331 = 1,1^3 = (11/10)^3

a'log b
= (10/11)'log (11/10)^3
= 3 . log (11/10) / log (11/10)^-1
= 3/-1
= -3 ✔