5log(x-1)=1-5log(x+3) tolong dijawab yahhh... terima kasih :)

...maaf ya kalo terlalu gelap...

⁵log(x - 1) = 1 - ⁵log(x + 3)
⁵log(x - 1) + ⁵log(x + 3)  = 1
⁵log((x - 1)(x + 3))  = 1
⁵log(x² + 2x - 3) = ⁵log 5
⇔ x² + 2x - 3 = 5
⇔ x² + 2x - 3 - 5 = 0
⇔ x² + 2x - 8 = 0
⇔(x + 4) (x - 2) = 0
 x = -4   atau    x = 2