Matematika

Pertanyaan

jika rumus fungsi f(x)=4x²-2,maka:
a. F(-3)= 4(....)²- ... = .... (.....) -2 = .... - ..... = .....
b. F(0) = ...... (0)² - ..... = ...... (.....)-2 = ..... -2 = ....
c.f(1) = .... (.....)² -2 = ..... (1)-....= ..... -...... =....
d.f(2)=......(...)²-....=4(....)-....=....-.....=....
Tolong bantu ya Kaka makasiyh sekalian caranya

1 Jawaban

  • f(x) = 4x²-2
    a. f(-3) = 4(3)²-2 = 4(9)-2 = 36-2 = 34
    b. f(0) = 4(0)²-2 = 4(0)-2 = 0-2 = -2
    c. f(1) = 4(1)²-2 = 4(1)-2 = 4-2 = 2
    d. f(2) = 4(2)²-2 = 4(4)-2 = 16-2 = 14

Pertanyaan Lainnya