sederhanakan : ½√2 - √3 ________ =............ √3 - 2√2

Bentuk Akar.

[tex]\displaystyle \frac{\frac{1}{2}\sqrt{2}-\sqrt{3}}{\sqrt{3}-2\sqrt{2}}\\ =\frac{\frac{1}{2}\sqrt{2}-\sqrt{3}}{\sqrt{3}-2\sqrt{2}}~\frac{\sqrt{3}+2\sqrt{2}}{\sqrt{3}+2\sqrt{2}}\\ =\frac{-\frac{2+3\sqrt{6}}{2}}{(\sqrt{3})^2-(2\sqrt{2})^2}\\ =\frac{2+3\sqrt{6}}{10}[/tex]