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Diketahui Q1=2mc, r=3dm, Fc=6N. Berapa Q2=. . . . ?

1 Jawaban

  • Q1 = 2 mC = 2 x 10⁻³ C
    r = 3 dm = 0,3 m = 3x10⁻¹ m
    Fc = 6 N
    k = 9 x 10⁹ N m² C⁻¹
    Q2= __?

    Fc = k Q1 Q2/r²
    6 = 9 x 10⁹ (2 x 10⁻³)Q2/(3x10⁻¹)
    6 = 6 x 10⁷ Q2
    Q2 = 6/(6 x 10⁷)
    Q2 = 10⁻⁷ C = 0,1 μC 

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