tentukan persamaan garis yang tegak lurus 2y + 2 = -7/4 (x - 7) dan melalui titik (-2,-3)... mohon jawabannya...

2y+2=-7/4(x-7)
2y+2 = -7/4x+49/7
m = x/y = [tex] \frac{ \frac{-7}{4} }{2} =[/tex] = -7/4 × 1/2 = -7/8

gradien tegak lurus = m₁ × m₂ = -1
         -7/8 × m₂ = -1
                   m₂ = -1×-8/7 = 8/7

persamaan
y-y₁ = m(x-x₁)
y+3 = 8/7(x+2)
   y = 8/7x + 16/7 - 3
7y = 8x + 16 - 21
7y = 8x - 5
7y - 8x + 5 = 0
8x - 7y - 5 = 0