Fisika

Pertanyaan

36°R=....°C=....°F=....K Minta BantuanNya Kk Dengan Cara

2 Jawaban

  • semoga membantu yaaaaa
    Gambar lampiran jawaban Lau111
  • 36°R = ... °C

    [tex] \frac{36 - 0}{80 - 0} [/tex] = [tex] \frac{t - 0}{100 - 0} [/tex]
    (36 × 100) = (t × 80)
    3600 = 80t
    t =[tex] \frac{3600}{80} [/tex]
    t = 45 °C

    36°R = ... °F

    [tex] \frac{36 - 0}{80 - 0} [/tex] = [tex] \frac{t - 32}{212 - 32} [/tex]
    (180 × 36) = 80t - 2560
    6480 = 80t - 2560
    9040 = 80t
    t = [tex] \frac{9040}{80} [/tex]
    t = 113 °F

    36°R = ... °K

    [tex] \frac{36 - 0}{80 - 0} [/tex] = [tex] \frac{t - 273}{373 - 273} [/tex]
    (100 × 36) = 80t - 21.840
    3.600 = 80t - 21.840
    25.440 = 80t
    t = [tex] \frac{25.440}{80} [/tex]
    t = 318 °K

    SEMOGA MEMBANTU

Pertanyaan Lainnya