Matematika

Pertanyaan

²log 18 - ²log 8√2 + ²log 1/27 - ²log ⅓

1 Jawaban

  • ²log 18 - ²log 8√2 + ²log 1/27 - ²log ⅓
    ²log(18.1/27)/(8√2.1/3)
    = ²log(2/3)/(8√2/3)
    = ²log(2/3).(3/8√2)
    = ²log(1/4√2)
    = ²log1/2^5/2
    = ²log2^-5/2
    = -5/2 . ²log2
    = -5/2

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