bentuk baku persamaan kuadrat a.(2-x)(x+3)=2(x-3) b.(x-1)^2=×-2

a.(2-x)(x+3)=2(x-3)
2x+6-x^-3x=2x-6
x^+2x-3x-2x+6+6 = 0
x^ - 3x + 12 = 0

b.(x-1)^2=×-2
(x-1)(x-1) = x-2
x^-2x+1-x+2 = 0
x^ - 3x + 3 = 0