f(x)= ax+b f(2)= 12 f(-3)= -23 tentukan : a. Nilai a dan b b. rumus fungsi tersebut

f(2) = 12
12 = a.2 + b
2a + b = 12
b = 12 - 2a
f(-3) = -23
-23 = a.-3 + b
-3a + b = -23
-3a + 12 - 2a = -23
-5a = -23 - 12
-5a = -35
a = -35/-5
a = 7
b = 12 - 2a
b = 12 - 2(7)
b = 12 - 14
b = -2
a. nilai a = 7 dan nilai b = -2
b. f(x) = ax + b
f(x) = 7x + (-2)
f(x) = 7x - 2