Metode substitusi 5x+3y=21 dan 4x+2y=16
Matematika
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Pertanyaan
Metode substitusi 5x+3y=21 dan 4x+2y=16
2 Jawaban
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1. Jawaban sjdhana
4x + 2y = 16
2y = 16 - 4x
y = 8 - 2x
subtitusi ke pers. 5x + 3y = 21
5x + 3(8 - 2x) = 21
5x + 24 - 6x = 21
-x = 21 - 24
-x = -3
x = 3
y = 8 - 2x
y = 8 - 2(3)
y = 8 - 6
y = 2 -
2. Jawaban TantoFebrian
Diketahui
5x + 3y = 21
4x + 2y = 16
Penyelesaian
4x + 2y = 16
2y = 16 - 4x
y = 16 - 4x / 2
y = 8 - 2x
5x + 3y = 21
5x + 3 (8 - 2x) = 21
5x + 24 - 6x = 21
- x = 21 - 24
- x = - 3
x = 3
Substitusi x = 3
y = 8 - 2x
y = 8 - 2 (3)
y = 8 - 6
y = 2